Calculate elevation in boiling point for 2 molal aqueous solution of glucose. (Given K_b(H_(2)O) = 0.5 kg mol^(-1) )
Calculate elevation in boiling point for 2 molal aqueous solution of glucose (Given: K_(b(H_2O) =0.5K kg mol^(-1)))
Equal volume of 1.0 M KCl and 1.0 M AgNO_(3) are mixed . The depression of freezing point of the resulting solution will be : ( K_(f) (H_(2)O) = 1.86K kg mol^(-1) , Assume : 1M = 1m)
KBr is 80% ionized in solution. The freezing point of 0.4 molal solution of KBr is : K_f (H_2O) = 1.86 (K kg)/("mole")
45 g of ethylene glycol C_(2)H_(6)O_(2) is mixed with 600 g of water. Calculate (a) the freezing point depression and (b) the freezing point of solution. Given K_(f)=1.86 K kg mol^(-1) .
The freezing point of a 0.05 molal solution of a non-electrolyte in water is: ( K_(f) = 1.86 "molality"^(-1) )
NARENDRA AWASTHI-DILUTE SOLUTION-Level 3 - Match The Column