A student is calculating the work during...

A student is calculating the work during a reversible isothermal process, shown by 2 moles of an ideal gas . By mistake he calculated the area as shown in PV graph (shaded area) equal to 49.26 L atm. Calculate the correct value of work (in L atm) during the process.

`-49.26 ln 2`

`49.26 ln 2`

`-24.63 ln 2`

`24.63 ln 2`

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A student is calculating the work during a reversible isothermal process , show by 2 mole of an ideal gas . He by mistake calculate the area as show in the PV graph (Shaded area ) equal to 49.26 liter atm . Calculate the correct value of work ( in litre atm ) during the process. (Given : R =0.0821 liter atm // "mole"/K)

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