Home
Class 12
CHEMISTRY
When a graph is plotted between log x//m...

When a graph is plotted between log `x//m` and log p, it is striaght line with an angle `45^(@)` and intercept `0.3010` on y-axis. If initial pressure is `0.3` atm, what will be the amount of gas adsorbed per gm of adsorbent?

A

`0.4`

B

`0.6`

C

`0.8`

D

`0.1`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • GRAPHICAL INTERPRETATION

    GRB PUBLICATION|Exercise F. Ionic Equilibrium|1 Videos
  • GRAPHICAL INTERPRETATION

    GRB PUBLICATION|Exercise Ionic Equilibrium|8 Videos
  • GRAPHICAL INTERPRETATION

    GRB PUBLICATION|Exercise E. Surface Chemistry|1 Videos
  • F-BLOCK ELEMENTS

    GRB PUBLICATION|Exercise Subjective type|7 Videos
  • HYDROCARBON (ALIPHATIC)

    GRB PUBLICATION|Exercise Previous years jee questions|28 Videos

Similar Questions

Explore conceptually related problems

When a graph is pplotted between log x//m and log p, it is straight line with an angle 45^(@) and intercept 0.3010 on y-axis. If initial pressure is 0.3 atm, what will be the amount of gas adsorbed per gm of adsorbent:

When a graph is plotted between log x//m and log p, it is straight line with an angle 45^(@) and intercept 0.3010 on y- axis . If initial pressure is 0.3 atm, what wil be the amount of gas adsorbed per gm of adsorbent :

When a graph is plotted between log x/m and log p, it is straight line with an angle 45^(@) and intercept 0.3010 on y - axis. If initial pressure is 0.3 atm, what will be the amount of gas adsorbed per gram of adsorbent : (Report your answer after multiplying by 10)

A graph between log (x/m) and log p is straight line at an angle of 45^(@) with intercept on y-axis equal to 0.3010. Calculate the amount of the gas adsorbed per gram of the adsobent when the pressure is 0.2 atm.

Graph between log x/m and log P is a straight line at angle of 45^(@) with intercept 0.4771 on y-axis. Calculate the amount of gas adsorbed in gram per gram of adsorbent when pressure is 3 atm.

Graph between log x//m and log p is a straight line inclined at an angle of 45^@ . When pressure is 0.5 atm and 1n k = 0.693 , the amount of solute adsorbed per gram of adsorbent will be:

Graph between log((x)/(m)) and log P is straight line at angle of 45^(@) with the intercept of 0.6020. The extent of adsorption ((x)/(m)) at a pressure of 1 atm is