According to collision theory for determining the variation of rate of reaction with temperature the rate constant,`k= Ae^(-Ea//RT).` For most of the practical purposes A and `E_(a`[Arrhenius factor and Activation energy] are temperature independent. However they may vary slightly.
Assuming the conditions given above answer the following questions.
For constant A and `E_(a),` which parameters when plotted will give a straight line with given slope?

Options

A. `"ln k vs T ,Slope" = (E_(a))/(R)`
B. `"ln k vs" 1/T "slope" = (E_(a))/(R)`
C. `"ln k vs"1/T,"slope"=(E_(a))/(R)`
D. `"ln k vs" T,"slope"=(E_(a))/(R)`

Answer

C