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`AbB` is a section of a straight wire carrying a current `I`. `P` is a point at a distance `d` from `AB`. The magnetic field at `P` due to `AB` has magnitude

A

`(mu_(0)I)/(4pid)(costheta_(1)+costheta_(2))`

B

`(mu_(0)I)/(4pid)(costheta_(1)-costheta_(2))`

C

`(mu_(0)I)/(4pid)(sin theta_(1)+sin theta_(2))`

D

`(mu_(0)I)/(4pid)(sin theta_(1)-sin theta_(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
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