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In the circuit shown, the symbols have t...


In the circuit shown, the symbols have their usual meanings. The cell has emf `varepsilon.X` is initially joined to `Y` for a long time. Then `X` is joined to `Z`. The maximum charge on `C` at any later time will be

A

`(varepsilon)/(Rsqrt(LC))`

B

`(varepsilonR)/(2sqrt(LC))`

C

`(varepsilonsqrt(LC))/(2R)`

D

`(varepsilonsqrt(LC))/(R)`

Text Solution

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The correct Answer is:
D
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