Home
Class 11
PHYSICS
Find the tensions in the two cords and t...

Find the tensions in the two cords and the accelerations of the blocks in figure-2.22 if friction is negligible. The pulleys are massless and frictionless, `m_(1) = 200 gm, m_(2) = 500 gm` and `m_(3) = 400 gm`, Take `g = 10m//s^(2)`.

`[0.94N, 3.06 N, 4.7 m//s^(2), 2.35 m//s^(2), 2.35 m//s^(2)]`

Promotional Banner

Topper's Solved these Questions

  • NEWTONS LAWS OF MOTION

    PHYSICS GALAXY - ASHISH ARORA|Exercise Practice Exerice|4 Videos

  • NEWTONS LAWS OF MOTION

    PHYSICS GALAXY - ASHISH ARORA|Exercise Practice Exercise|23 Videos

  • NEWTONS LAWS OF MOTION

    PHYSICS GALAXY - ASHISH ARORA|Exercise Unsolved Numerical Problem|81 Videos

  • LINEAR MOMENTUM & ITS CONSERVATION

    PHYSICS GALAXY - ASHISH ARORA|Exercise exercise 1.3|3 Videos

  • RIGID BODIES AND ROTATIONAL MOTION

    PHYSICS GALAXY - ASHISH ARORA|Exercise Unsolved Numerical|63 Videos

Similar Questions

Explore conceptually related problems

1 kg m//s^(2) =___gm- mm//s^(2)

Find the relation between acceleration of the two blocks m_(1) and m_(2) . Assume pulleys are massless and frictionless and the strings are inextensible .

Find the tension in the tape and the linear acceleration of the cylinder up the incline, assuming there is no slipping. ( Take M = 4m and g =10 m//s^(2) )

If the tension in the string in the figure. Is N and the acceleration of each block is 0.5 m/s^2 , find the friction coefficients at the two contacts with h blocks.

Find the acceleration of the two blocks shown in figure-2.101.Take g=10m//s^(2) [2m//s^(2), 2m//s^(2)]

In the system shown in the adjoining figure, the acceleration of the 1 kg mass is m//s^(2) . (take g = 10 m//s^(2) )

Find the acceleration of masses m_(1) and m_(2) connected by an inextensible string, shown in figure-2.13(a). The string and pulley are assumed to be massless and frictionless.

In figure assume that there is nagligible friction between the blocks and table. Compute the tension in the cord connecting m_(2) and the pulley and acceleration of m_(2) if m_(1) = 300 g , m_(2) = 200 g and F = 0.40N

In the figure ( g = 10 m//s^(2) ) .Acceleration of 2kg block is :

In the system of pulleys shown what should be the value of m_(1) such that 100 gm remains at rest : (Take g = 10 m//s^(2) )

PHYSICS GALAXY - ASHISH ARORA-NEWTONS LAWS OF MOTION-Practice Exerice 2.1
  1. Find the tensions in the two cords and the accelerations of the blocks...

    Text Solution

    |