A homogeneous chain of length 2l and mass M lies on an absolutely smooth table. A small part of the chain hangs from the table. At the initial moment, the part of the chain lying on the table is held and released, after which the chain begins to slide off the table under the weight of the hanging end. Find the velocity of the chain when the length of the hanging part is equal to `x(x lt I)`. Also calculate the acceleration and the force with which it acts on the edge of the table.

Answer

`[xsqrt((g)/(2l)),(xg)/(2l),(sqrt(2)Mg)/(4l^(2))(2l-x)x]`