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A 12kg monkey climbs a light rope.The ro...

A 12kg monkey climbs a light rope.The rope passes over a pulley and is attached to a 16kg bunch of bananas resting on floor. Mass and friction in the pulley are negligible so that the pulley's only effect is to reverse the direction of the rope. What is the maximum acceleration the monkey can have without lifting the bananas ? (Take `g=10m//s^(2)`)

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The correct Answer is:
`[10//3 m//s^(2)]`
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A 12 kg monkey climbs a light rope as shown in figure. The rope passes over a pulley and is attached to a 16 kg bunch of bananas. Mass and friction in the pulley are negligible so that the pulley's only effect is to reverse the direction of the rope. What is the maximum acceleration the monkey can have without lifting the bananas?

A 20 kg monkey has a firm hold on a light rope that passes over a frictionless pulley and is attached to a 20 cm bunch if bananas. The monkey looks upwards , sees the bananas and starts to climb the rope to get them. (a) As the monkey climbs ,do the bananas move up , move down or remain at rest? (b) As the monkey climbs ,does the distance between the lonkey and the banana decrease, increase or remain contact? (c) The monkey releases her hold on the rope .What happens to the distance between the monkey and the bananas while she is falling ? (d) Before reaching the ground , the monkey grabs the rope of stop har fall. What do the bananas do?

A monkey of mass 20kg is holding a vertical rope. The rope will not break when a mass of 25kg is suspended from it but will break it the mass exeeds 25kg . What is the maximum acceleration with which the monkey can climb up along the rope? (g=10m//s^(2)) .

A monkey of 25 kg is holding a vertical rope. The rope does not break if a body of mass 30 kg is suspended with the rope exceeds 30 kg. What will be the maximum acceleration with which the monkey can climb up along the rope ? ( Take , =10 ms^(-2) )

A body of mass 40 kg wants to climb up a rope hanging vertically. The rope can withstands a maximum tension of 500 N. What is the maximum acceleration with which the boy can climb rope? Tak e g=10m//s^(2)

As shown in figure a monkey of 20g mass is holding a light rope that passes over a frictionless pulley. A bunch of bananas of the same mass is tied to the other end of rope. Inorder to get access to the bunch the monkey starts climbing the rope. The distance between the monkey and the bananas is

A monkey is a reston a weightless rope which goes over a pulley and is tied to a bunch of bananas at the other end. The weight of the bunch of bananas isexactly the same as that of the monkey. The pulley is frictionless and weightless. The monkey starts to climb up the rope to reach the bananas. As he climbs, the distance between him and the bananas will

A 40 kg boy climbs a rope that passes over an ideal pulley. The other end of the rope is attached to a 60 kg weight placed on the ground. What is the maximum upward acceleration the boy can have without lifting the weight ? If he climbs the rope with upward acceleration 2 g, with what acceleration the weight will rise up ?

A body of mass 60 kg is holding a vertical rope . The rope can break when a mass of 75 kg is suspended from it. The maximum acceleration with which the boy can climb the rope without breaking it is : ( g = 10 m//s^(2))

PHYSICS GALAXY - ASHISH ARORA-NEWTONS LAWS OF MOTION-Unsolved Numerical Problem
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