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A bar of mass m is pulled by means of a thread up an inclined plane forming an angle `theta` with the horizontal as shown in figure-2.211. The coefficient of friction is `mu`. Prove that
(a)`alpha=tan^(-1)mu`, where `alpha` is the angle which the thread must from with the inclined plane for the tension of the thread to be minimum.

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The correct Answer is:
`T_("min")=(mgsintheta+mumgcostheta)/(sqrt(1+mu^(2))`
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