An object of mass `40kg` and having velocity `4 m//s` collides with another object of mass `60 kg` having velocity `2 m//s` . The loss of energy when the collision is perfectly inelastic is

Explanation

`m_91) = 40kg, m_(2) = 60kg, v_91) = 4ms^(-1) , v_(2) = 2ms^(-1)`
`therefore DeltaK = (1/2)(m_(1)m_(2))/(m_(1) + m_(2))(v_(1) - v_(2))^(2) = 1/2(40 xx 60)/(40 + 60)(4-2)^(2) = 48J`