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Two perfectly elastic particles A and B ...

Two perfectly elastic particles `A` and `B` of equal masses travelling along a line joining them with velocities `15 m//s` and `10m//s` respectively collide. Their velocities after the elastic collision will be (in m/s) respectively

A

`10 ms^(1-), 10ms^(1-)`

B

`15 ms^(-1), 15 ms^(-1)`

C

`10ms^(-1) , 15 ms^(-1)`

D

`15 ms^(-1), 10 ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C

`v_(2) = (m_(2)-m_(1))/(m_(1)+m_(2))u_(2) + (2m_(1)u_(1))/(m_(1)+m_(2)`
`v=(2Mu)/(M+m)`
`v=(2u)/(1+m/m)`
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