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A body of mass m moving with velocity v ...

A body of mass m moving with velocity v collides head on with another body of mass 2 m which is initially at rest. The ratio of K.E. of colliding body before and after collision will be

A

`1:1`

B

`2:1`

C

`4:1`

D

`9:1`

Text Solution

Verified by Experts

The correct Answer is:
B
e = (Relative velocity of separation)/(Relative velocity of approach) = `(5-2)/(8-2) = 1/2`
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