A bullet of mass m is fired into a block of wood of mass M which hangs on the end of pendulum and gets embedded into it. When the bullet strikes with maximum rise R. Then, the velocity of the bullet is given by

Options

A. `(M)/(m + M)(sqrt(2gR)`
B. `(M+m)/(m) sqrt(2gR)`
C. `(M/m)sqrt(2gR)`
D. None of these

Answer

B

Explanation

`v_(') = sqrt(2gR)`
From conservation of linear momenum ,
`mv = (M+m)v^(')`
`v = (M+m)/(m)sqrt(2gR)`