A particle of mass m moving with a speed...

A particle of mass `m` moving with a speed `v` hits elastically another staionary particle of mass `2m` on a smooth horizontal circular tube of radius `r`. Find the time when the next collision will take place?

`(2pir)/(v)`

`(4pir)/(v)`

`(3pir)/(2v)`

`pir)/(v)`

Text Solution

Verified by Experts

The correct Answer is:

Relative speed of seperation = relative speed of approach
`therefore` Time of next collision = `(2pir)/v`

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