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In a gravity free space, man of mass M s...

In a gravity free space, man of mass `M` standing at a height `h` above the floor, throws a ball of mass `m` straight down with a speed `u`. When the ball reaches the floor, the distance of the man above the floor will be.

A

`h(1+(m/M))`

B

`(1+(M/m))h`

C

h

D

`(m/M)h`

Text Solution

Verified by Experts

The correct Answer is:
A
Center of mass will remain at height h.
`therefore h_(CM) = (mxx0+MH)/(m+M) = h`
`therefore H = h(1 + (m/M))`
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