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If the kinetic energy of a body increase...

If the kinetic energy of a body increases by `0.1 %` the percent increase of its momentum will be

A

`0.05%`

B

`0.1%`

C

`1.0%`

D

`10%`

Text Solution

Verified by Experts

The correct Answer is:
A

`p = sqrt(2mE) therefore p alpha sqrt(E), (dp)/p = 1/2dk/k`
Percentage increase in p = 1/2(percentage increase in E)`
=1/2 (0.1%)= 0.05%`
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