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A train of mass M is moving on a circula...

A train of mass M is moving on a circular track of radius R with constant speed `v`. The length of the train is half of the perimeter of the track. The linear momentum of the train will be

A

`piMv`

B

`(2Mv)/(pi)`

C

`(piMv)/2)`

D

Mv

Text Solution

Verified by Experts

The correct Answer is:
B
`p_(net) = int dp sintheta = (int_(0)^(pi)(M/pi.d(theta))v.sintheta = (2Mv)/pi`
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