Home
Class 11
PHYSICS
In the diagram shown in figure mass of b...

In the diagram shown in figure mass of both the balls in same. Match the following columns.

`{:("Column1","Column2"),("A For" v^(')=v,"P e=0"),("B For" v^(')=v//2,"Q e=1"),("C For" v^(')= 3//4v,"R e=1/2"),("-","(S data is insufficient"):}`

Text Solution

Verified by Experts

The correct Answer is:
A `rightarrow`q, B `rightarrow`p, C `rightarrow`r
When e = 1 collision is elastic and equal masses exchange their velocities.
For e=0, collisioin is perfectly inelastic. Hence, velocity of each will remain half.
In the last case, when `v_(2) = 3/4v`
Then, `v_(1) = v/4` ( from conservation of momentum)
`e = ((3v)/4-(v/4))/v = 1/2`
Promotional Banner

Topper's Solved these Questions

  • CENTRE OF MASS

    DC PANDEY|Exercise Medical entrances gallery|27 Videos

  • CENTRE OF MASS

    DC PANDEY|Exercise Assertion and reason|21 Videos

  • CALORIMETRY AND HEAT TRANSFER

    DC PANDEY|Exercise Medical entrance s gallery|38 Videos

  • CENTRE OF MASS, IMPULSE AND MOMENTUM

    DC PANDEY|Exercise Comprehension type questions|15 Videos

Similar Questions

Explore conceptually related problems

In the V-T graph shown in the figure match the following columns.

In the part of circuit shown in figure, match the following two columns for V_(AB)

Let V and E denote the gravitational potential and gravitational field at a point. Then, match the following columns {:(,"Column-I",,"Column-II"),("(A)",E = 0","V = 0,"(p)","At centre of spherical shell"),("(B)",E ne0","V=0,"(q)","At centre of solid sphere"),("(C)",V ne0","E=0,"(r)","At centre of circular ring"),("(D)",V ne0","E ne0,"(s)","At cetre of two point masses of equal magnitude"),(,,"(t)","None"):}

In the circuit diagram shown in Figure E=18V , L=2H, R_(1)=3Omega , R_(2)=6Omega . Switch S is closed at t=0 Match the following:

Match the following: {:("Column A"," Column B"),((1)V^(4+),(a)" Colourless"),((2)Ti^(3+),(b)" Pink"),((3)Ti^(4+),(c) " Purple"),((4)Mn^(2+),(d)" Violet"):}

In the circuit shown in figure, E = 10 V, r = 1Omega , R = 4Omega and L = 5H. The circuit is closed at time t = 0. Then, match the following two columns. {:(,"Column I",,"Column II"),(A.,V_(AD)" at t = 0",p,4 V),(B.,V_(BC)" at t = 0",q,8 V),(C.,V_(AB)" at t ="oo,r.,0V),(D.,V_(AD)" at t"=oo,s.,10V):}

On the surface of earth acceleration due gravity is g and gravitational potential is V. Match of following columns {:(,"Column-I",,"Column-II"),("(A)","At height h=R, value of g","(p)","Decreases by a factor" (1)/(4)),("(B)","At depth " h =(R)/(2)"," "value of g","(q)","Decrease by a factor" (1)/(2)),("(C)","At height "h=R",""value of V","(r)","Increase by a factor" (11)/(8)),("(D)","At height "h=(R)/(2)"," "value of V","(s)","Increase by a factor 2"),(,,"(t)","None"):}