Two sphere `A and B` of masses `m_(1) and m_(2)` respectivelly colides. A is at rest initally and `B` is moving with velocity `v` along x-axis. After collision `B` has a velocity `(v)/(2)` in a direction perpendicular to the original direction. The mass `A` moves after collision in the direction.

Options

A. same as that of B
B. opposite to that of B
C. `theta = tan^(-)(1/2)` to the X-axis
D. `theta = tan^(-)(-1/2)` to the X-axis

Answer

C

Explanation

Here ,`p_(i) = m_(2)vhat(i) + m_(1) xx 0`

`p_(f) = m_(2)v//2hat(j) + m_91) xx v_(1)`
`v_(1) = (m_(2)/m_(1))hat(i) - (m_(2)/m_(1))v/2hat(j)` from this equatin, we can find
`tantheta = 1/2`
`theta = tan^(-1)(1/2)` to the X-axis.