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If a calculated value 2.7465 g contains only three significant figures, the two insignificant digits in it are
The number of significant digits in 0.001001 is :-
If there are three significant digits in 0.abc , then what are the possible values of a, b and c?
Let N be the number of significant digits in 100^(23) and M be the number of zeros after decimal but before significant digit in e^(-23) Then which of the following is(are) correct? (Use: log_(10)e=0.434)
Write the number of significant digits in a 1001, b. 100.1, c.100.10 d. 0.001001.
Round off to three significant digits (i) 0.03927kg (ii) 4.085xx10^8s
Find the number of significant digits in measurement of 0.00100010
1.2 xx 36.72 = 44.064 ~~44 The least number of significant digits in the measured values are two. Hence, the result when rounded off to two significant digits become 44. Therefore, the answer is 44.
In expressing a length 81.472km as nearly as possible with three significant digits,find the percentage error
