Let `[epsilon_(0)]` denote the dimensional formula of the permittivity of the vacuum, and `[mu_(0)]` that of the permeability of the vacuum. If `M = mass ,L = length, T = time and I = electric current`,

Options

A. `[epsilon_(0)]=[M^(-1)L^(-3)T^(2)l]`
B. `[epsilon_(0)]=[M^(-1)L^(-3)T^(4)l^(2)]`
C. `[mu_(0)]=[MLT^(-2)l^(-2)]`
D. `[mu_(0)]=[ML^(2)T^(-1)l]`

Answer

B, C, D