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A mass of 2 kg is suspended from a vert...

A mass of 2 kg is suspended from a vertical spring. An additional force of 2.5 N stretches it by 1 cm. (i) Calculate the force constant. (ii) Calculate the frequecny of oscillations, if the spring is stretched by the given force and then released.

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Knowledge Check

  • A mass M is suspended from a massless spring. An additional mass m stretches the spring further by a distance x . The combined mass will oscillate with a period

    A
    `2pisqrt({((M + m)x)/(mg)})`
    B
    `2pi sqrt ({(mg)/((M + m)x)})`
    C
    `2pi sqrt ({((M + m))/(mgx)})`
    D
    `(pi)/(2) sqrt ({(mg)/((M + m)x)})`

  • A mass suspended on a vertical spring oscillates with a period of 0.5s . When the mass is allowed to hang at rest, the spring is stretched by

    A
    `3.1cm`
    B
    `6.2cm`
    C
    `9.3cm`
    D
    `12.4cm`

  • A spring has a force constant k and a mass m is suspended from it the spring is cut in two equal halves and the same mass is suspended from one of the halves. If the frequency of oscillation in the first case is n, then the frequency in the second case will be

    A
    2 n
    B
    `n//sqrt(2)`
    C
    n
    D
    `sqrt(2)n`

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