An impulsive force gives an initial velocity of- `1.0 m s^(-1)` to the mass in the unstretched spring position [sec Fig. 16.2]. What is the amplitude of motion ? Give x as a function of time t for the oscillating mass. Given m=3 kg and `k=1200 Nm^(-1)`.

In example 34, let us take the position of the mass, when the spring is unstretched, as x=0, and the direction from left to right as the positive direction of X-axis. Give x as a function of time t for the oscillating mass, if at the moment we start the stop watch (t=0), the mass is (i) at the mean position (ii) at the maximum stretched position (iii) at the maximum compressed position. In what do these different functions of SHM differ ? Frequency, amplitude or initial phase ?

An object of mass 10 kg is moving with an initial velocity of 10 m s^(-1) . A constant force acts for 4 s on the object giving it a speed of 2 m s^(-1) in the opposite direction. Find the acceleration and force.

A 0.20kg object mass attached to a spring whose spring constant is 500N/m executes simple harmonic motion. If its maximum speed is 5.0m/s, the amplitude of its oscillation is

A mass m = 8kg is attached to a spring as shown in figure and held in positioin so that the spring remains unstretched. The spring constant is 200 N/m. The mass m is then released and begins to undergo small oscillations. The maximum velocity of the mass will be (g=10m/ s^(2))

The velocity of the particle of mass m as a function of time t is given by v = Aomega.cos[sqrt(K/m)t] , where A is amplitude of oscillation. The dimension of A/K is

A ball of mass 0.2 kg moves with a velocity of 20m//sec and it stops in 0.1 sec , then the force on the ball is

A mass m attached to a light spring oscillates with a period of 2 s. If the mass is increased by 2 kg, the period increases by 1 s. Then the value of m is