The simple harmonic motions are represented by the equations:
`y_(1)=10sin((pi)/(4))(12t+1), y_(2)=5(sin3pit+sqrt(3)))`

Two simple harmonic motions are represented by the equations. y_(1)=10"sin"(pi)/(4)(12t+1),y_(2)=5(sin3pt+sqrt(3)cos3pt) the ratio of their amplitudes is

Two simple harmonic motions are represented by the equations y_(1) = 10 sin (3pit + (pi)/(4)) and y_(2) = 5 (3 sin 3 pi t+sqrt(3) cos 3 pi t) . Their amplitudes are in the ratio of

Two simple harmonic motions are represented by the equations y_(1) = 8 sin(pi)/(4)(10t + 2),y_(2) = 6(sin 5pit + sqrt(3) cos 5omegat) IF the ratio of amplitudes of y_(1) and y_(2) is alpha and their respective ratio of time periods is beta , then find beta//alpha .

Two simple harmonic motions are represented by the equations y_(1) = 10 sin(3pit + pi//4) and y_(2) = 5(sin 3pit + sqrt(3)cos 3pit) their amplitude are in the ratio of ………… .

Two simple harmonic motions are represented by the following equations y_1=10sinpi/4(12t+1) y_2=5(sin 3pit+sqrt3cos3pit) Find out the ratio of their amplitudes. What are the time periods of two motions?

Two simple harmonic motion, are represented by the equations y _(1) = 10 sin ( 3 pi t + (pi)/(3)) y _(2) = 5 ( sin 3 pi t + sqrt3 cos 3 pi t ) Ratio of amplitude of y _(1) to y _(2) = x :1. The value of x is __________

Two simple harmonic motion are represent by the following equations y_(1) = 10 sin (pi//4) (12 t + 1) y_(2) = 5 (sin 3 theta t + sqrt3 cos 3 theta t) Here t is in seconds. Find out the ratio of their amplitudes.What are the time period of the two motion?

Two simple harmonic motions are represented by the equations. x_(1)=5sin(2pit+(pi)/(4)),x_(2)=5sqrt(2)(sin2pit+cos2pit) find the ratio of their amplitudes.

Two simple harmonic motions are represented by the equations y_(1)=2(sqrt(3)cos3 pi t+sin3 pi t) and y_(2)=3sin(6 pi t+pi/6)

Two simple harmonic motions are represented by the equations : x_1 = 5 sin (2 pi t + pi//4 ) , x_2 = 5^(2) (sin2 pi t + cos2 pi t) What is the ratio of their amplitudes ?