A point particle of mass 0.1 kg is executing SHM of amplitude 0.1m. When the particle passes through the mean position, its kinetic energy is `8xx10^(-3)J`. Obtain the equation of motion of the particle if the initial phase of oscillation is `45^(@)`

A point particle of mass 0.1kg is executing SHM of amplitude 0.1m . When the particle passes through the mean position, its kinetic energy is 8xx10^-3J . Obtain the equation of motion of this particle if the initial phase of oscillation is 45^@ .

A point particle if mass 0.1 kg is executing SHM of amplitude 0.1 m . When the particle passes through the mean position, its kinetic energy is 8 xx 10^(-3)J . Write down the equation of motion of this particle when the initial phase of oscillation is 45^(@) .

A particle of mass 0.2 kg is excuting SHM of amplitude 0.2 m. When it passes through the mean position its kinetic energy is 64 xx 10^(-3) J . Obtain the equation of motion of this particle if the initial phase of oscillation is pi//4 .

A point particle of mass 0.1kg is executing SHM with amplitude of 0.1m . When the particle passes through the mean position. Its K.E. is 8xx10^(-3)J . Obtain the equation of motion of this particle if the initial phase of oscillation is 45^(@) .

A particle of mass 100 g is executing S.H.M. with amplitude of 10 cm. When the particle passes through the mean position at t = 0. Its kinetic energy is 8 mJ. The equation of simple harmonic motion, if initial phase is zero is

In the equation of motion of a particle y = 0.5 sin (0.3t + 0.1) , the initial phase of motion is -

A body of mass 0.1 kg is executing a simple harmonic motion of amplitude 0.2 m. When the body passes through the mean position, its kinetic energy is 8xx10^(-3) J. The initial phase of oscillation is 60. What is the equation of motion of the body ?

A particle of mass m is executing SHM about its mean position. The total energy of the particle at given instant is