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Find (dy)/(dx)in the following:y=tan^(-...

Find `(dy)/(dx)`in the following:`y=tan^(-1)((3x-x^3)/(1-3x^2)),-1/(sqrt(3)) < x < 1/(sqrt(3))`

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To find \(\frac{dy}{dx}\) for the function \[ y = \tan^{-1}\left(\frac{3x - x^3}{1 - 3x^2}\right) \] we can use the chain rule and the derivative of the inverse tangent function. Here are the steps to solve the problem: ...
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