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Find (dy)/(dx) in the following:y=sin^(...

Find `(dy)/(dx)` in the following:`y=sin^(-1)((1-x^2)/(1+x^2))`,`0 lt x lt 1`

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To find \(\frac{dy}{dx}\) for the function \(y = \sin^{-1}\left(\frac{1 - x^2}{1 + x^2}\right)\), we will follow these steps: ### Step 1: Rewrite the function Let: \[ y = \sin^{-1}\left(\frac{1 - x^2}{1 + x^2}\right) \] ...
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