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Find (dy)/(dx) in the following:y=sec^(...

Find `(dy)/(dx)` in the following:`y=sec^(-1)(1/(2x^2-1))`

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To find \(\frac{dy}{dx}\) for the function \(y = \sec^{-1}\left(\frac{1}{2x^2 - 1}\right)\), we will follow these steps: ### Step 1: Rewrite the Function We start with the given function: \[ y = \sec^{-1}\left(\frac{1}{2x^2 - 1}\right) \] ...
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