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A body of mass 5 kg is moving in a strai...

A body of mass 5 kg is moving in a straight line. The relation between its displacement and time t is given by `x=(t^(3)-2t-10)` metre. What is the force acting onit at the end of second?

A

150 N

B

120N

C

100N

D

80N

Text Solution

Verified by Experts

The correct Answer is:
A
Given : Displacement (x) `=t^(3)-2t-10`
`therefore` Velocity (v) `=(dx)/(dt) = 3t^(2)-2`
`and a = (dv)/(dt) = 6t`
When `t=5s, a=6xx5 = 30 m//s^(2)`
`therefore F= ma= 5xx30= 150N`
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