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A force F appllied to a body(A)of mas m(...

A force F appllied to a body(A)of mas `m_(1)` produces an acceleratioin of `4m//s^(2)`. If the same force F is applied to another body (B) of mass `m_(2)`, then an acceleratiionof `10m//s^(2)`, produced in the body. A and B are the tied together and the same force is applied to the combined body. What is the acceleration of the system?

A

`10/7m//s^(2)`

B

`20/7m//s^(2)`

C

`5/3m//s^(2)`

D

`7/20m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`because F= m xxa therefore m_(1) = (F)/(4) and m_(2)= (F)/(10)`
and the combined mass (M) `=m_(1)+m_(2)`
`=(F)/(4)+(F)/(10)= (14F)/(40)`
`therefore` Acceleration of the system `= (F)/(M)= (F)/(14F//40)`
`=(40)/(14)= (20)/(7) m//s^(2)`
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