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While launching a rocket of mass 2xx10^(...

While launching a rocket of mass `2xx10^(4)` kg, a force of `5xx10^(5)N` is applied for 20s. What is the velocity attained by the rocket at the end of 20s?

A

300m/s

B

350 m/s

C

450 m/s

D

500 m/s

Text Solution

Verified by Experts

The correct Answer is:
D
Impulse = Change in momentum
`therefore F xx t= m(v-u), " where " u=0`
`5xx10^(5) xx 20 = 2xx10^(4) xx v`
`therefore v= (100xx10^(5))/(2xx10^(4))= 500m//s`
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