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A triangular block of mass M with angle ...

A triangular block of mass M with angle 30º, 60º, 90º rests with its 30º– 90º side on a horizontal smooth fixed table. A cubical block of mass m rests on the 60º – 30º sideofthe triangular block. What horizontal acceleration a must M have relative to the stationary table so that m remains stationary with respect to the triangular block [M = 9 kg, m = 1 kg]

A

`g`

B

`g/(sqrt(2))`

C

`g/(sqrt(3))`

D

`g/2`

Text Solution

Verified by Experts

The correct Answer is:
C

For equilibrium, `Ncos 30^(@)= mg`
and `N sin 30^(@)= ma" " therefore tan 30^(@)= (a)/(g)`
`therefore a = g tan 30^(@) = gxx (1)/( sqrt(3)) = (g)/(sqrt(3))`
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