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500 steel ballls each of mass 1 gram str...

500 steel ballls each of mass 1 gram strike normally one sq. cm area of a metal plate per second, with a velocity of 10 m/s and rebound with the same velocity. What is the pressure exerted by the balls on the surface of the plate?

A

`10^(4)N//m^(2)`

B

`10^(5)N//m^(2)`

C

`2xx10^(5)N//m^(2)`

D

`4xx10^(4)N//m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Pressure `=("Force")/("Area")`
and Force `=("Change in momentum")/("Time")`
The change in momentum of each ball when it strikes and rebounds from the surface `=mv- (-mv)= 2mv`
`therefore F= (n(2mv))/(t)= (500xx2xx1xx10^(-3)xx10)/(1)`
`therefore F= 10N`
`therefore P=(F)/(a)= (10)/((1cm)^(2))= (10)/((10^(-2))^(2))= (10)/(10^(-4))`
`therefore P= 10^(5) N//m^(2)`
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