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Two balls of same mass are dropped from ...

Two balls of same mass are dropped from the same height onto the floor. The first ball bounces upwards from the floor elastically. The second ball stricks to the floor. The first applies an impulse to the floor of `I_(1)` and the second applies an imupulse `I_(2)`. The impulses obey :-

A

`I_(1)=I_(2)`

B

`I_(1)=(I_(2))/2`

C

`I_(1)=2I_(2)`

D

`I_(1)=(I_(2))/4`

Text Solution

Verified by Experts

The correct Answer is:
C

Impulse = Change in momentum
Let v be the velocity of the first ball when it strikes the ground. Its momentum = mv. It suffers an elastic collision.
It goes up with velocity v or momentum mv.
`therefore` Change in momentum`=mv-(-mv)= 2mv`
The second ball also strikes the ground with a velocity v, its momentum is mv and as it sticks to ground, v = 0, momentum after collision = 0.
`therefore ` Change in its momentum `=mv-0=mv`
This is equal to `I_(2)`.
Thus `I_(1)= 2mv and I_(2)= mv`
`therefore I_(1) = 2I_(2)`
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