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The mass of a rocket is 500 kg and the r...

The mass of a rocket is 500 kg and the relative velocity of the gases ejecting from it is 250 m/s with respect to the rocket. The rate of burning of the fuel in order to give the rocket an initial acceleration `20 m//s^(2)` in the vertically upward direction `g = 10 m/s^(2)`, will be -

A

300 kg/s

B

60 kg/s

C

90 kg/s

D

30 kg/s

Text Solution

Verified by Experts

The correct Answer is:
B
Thrust required `=m(a+g)=u(dm)/(dt)`
`therefore `Rate of burning of the fuel `((dm)/(dt))= (m(a+g))/(u)`
`therefore (dm)/(dt) = (500 (20+10))/(250)= 2xx30=60kg//s`
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