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A man tries hard to push a loaded truck ...

A man tries hard to push a loaded truck but fails to move it. In tis case he does

A

negative work

B

postive work

C

zero work

D

maximum +ve work

Text Solution

Verified by Experts

The correct Answer is:
C

For the inclined plane, `sin theta=2/12=1/6`
When the box reaches its highest point A, its total energy `=P.E.+K.E. =mgh +1/2mv^(2)`
`=50 xx 10 xx 2 +1/2 xx 50 xx 2 xx 2`
`=1000+100=1100J ..........(1)`
The upward motion of the block is opposed by the force of friction.
Resultant work=Work done by applied force `(W_(1))`-Work done against friction `(W_(2))`
`=F xx L -W_(2)`
`=100 xx 12-W_(2) ...........(2)`
`therefore` From (1) and (2), 1100J=1200-`W_(2)`
`therefore W_(2)=1200-1100=100J`
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