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The force acting on a bod moving paralle...

The force acting on a bod moving parallel to the X-axis is `F=3x+2x^(2)`. What is the work done in displacing the body from `x=1` to `x=2`?

A

`65/6` units

B

`25/6` units

C

`55/6` units

D

`35/6` units

Text Solution

Verified by Experts

The correct Answer is:
C
Work done =mgh
Length of the hanging part is `L/3` and Mass of the hanging part `=M/3`

The centre of mass of the hanging part is at a distance `L/6` from the top of the table `therefore h=L/6`
Work done W=mgh `=(M/3)g (L/6) =(MgL)/(18)`
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