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A uniform chain of length L and mass M i...

A uniform chain of length `L` and mass `M` is lying on a smooth table and one-third of its length is hanging vertically down over the edge of the table. If g is the acceleration due to gravity, the work required to pull the hanging part on to the table is

A

`(MgL)/18`

B

`(MgL)/9`

C

`MgL`

D

`(MgL)/3`

Text Solution

Verified by Experts

The correct Answer is:
A
`s=vecr_(2)-vecr_(1)`
`=(14-3)hati+(13-2)hatj+[(9-(-6))]hatk`
`=11 hati+11hatj+15hatk`
Work done `=vecF. vecs`
`=(4 hati+hatj+3hatk). (11hati+11hatj+15hatk)`
`therefore W=4 xx 11 +1 xx 11+3 xx 15`
`therefore W=100J [therefore hati. hati=hatj.hatj=hatk.hatk=1]`
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