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If the momentum of a body is increased b...

If the momentum of a body is increased by 50%, then the percentage increase in its kinetic energy is

A

2

B

1

C

1.25

D

0.5

Text Solution

Verified by Experts

The correct Answer is:
C
If the K.E. of the body is increased by 300% the new K.E. becomes `K'=K+(300)/(100)K=4K`
The relation between K.E. (K) and linear momentum (P) is given by `P^(2)=2mK`
`P^(2)=2mK=2m(4K)=8mK`
`therefore P=sqrt(4 xx 2mK)=sqrt(4 xx P^2)=2P`
Percentage change (increase) in P
`((P-P)/(P)) xx 100=((2P-P)/(P)) xx 100=100%`
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