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If kinetic energy of a body is increased...

If kinetic energy of a body is increased by 300%, then percentage change in momentum will be

A

1

B

1.5

C

0.732

D

2.5

Text Solution

Verified by Experts

The correct Answer is:
A
The relation between K.E. (K) and momentum (P) is given by `P=sqrt(2mK)`
`It is given by P_(1)=P_(2)`
`therefore sqrt(2m_(1)K_(1))=sqrt(2m_(2)k_(2))`
`m_(1)/m_(2)=K_(2)/K_(1)`
But `m_(1) gt m_(2) therefore K_(2) gt K_(1) or K_(1) lt K_(2)`
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