A particle of mass m1 is moving with a velocity `v_(1)` and another particle of mass `m_(2)` is moving with a velocity v2. Both of them have the same momentum but their different kinetic energies are E1 and E2 respectively. If `m_(1) gt m_(2)` then

Options

A. `K_(1)ltK_(2)`
B. `K_(1)gtK_(2)`
C. `K_(1)=K_(2)`
D. `(K_(1))/(K_(2))`

Answer

A

Explanation

When the ball is projected vertically upwards with a speed v, its `K.E. =1/2mv^(2)`. When it reaches the maximum height, it has maximum P.E.=mgh
Maximum P.E.=Maximum K.E. `=1/2 mv^(2)=1/2 xx 0.5 xx (4)^(2)`
`=1/2 xx 1/2 xx 4 xx 4 =4J`