Home
Class 11
PHYSICS
A spring of force constant 800N//m has a...

A spring of force constant `800N//m` has an extension of 5cm. The work done in extending it from 5cm to 15cm is

A

24J

B

32J

C

8J

D

16J

Text Solution

Verified by Experts

The correct Answer is:
C

K.E. of the block =Energy of the compressed spring `1/2 Mv^(2)=1/2kL^(2)`
`therefore v^(2)=(Kl^(2))/(M) therefore v=sqrt((k)/(M))L`
Maximum momentum of the block `=Mv=Msqrt((k)/(M))L =sqrt(kM)L`
Promotional Banner

Topper's Solved these Questions

  • FORCE, WORK AND TORQUE

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|10 Videos
  • FRICTIONAL IN SOLIDS AND LIQUIDS

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|10 Videos

Similar Questions

Explore conceptually related problems

A spring of force constant 800 Nm^(-1) is stretched initially by 5 cm . The work done in stretching from 5 cm to 15 cm is

A spring of force constant 4000N/m when stretched by 8 cm, the potential energy stored in it will be?

A spring with spring constant k is extended from x=0 to x=x_(1) . The work done will be

An extension of 10 cm is produced in a spring (spring constant = 1000 Nm^(-1) ). Calculate the work done to increase the extension from 10 cm to 20 cm.

K is the force constant of a spring. The work done in increasing its extension from l_1 to l_2 will be

Two springs of force constant 100N//m and 150N//m are in series as shown the block is pulled by a distance of 2.5 cm to the right from equilibrium position what is the ratio of work done by the spring at left to the work done by the spring at right: