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A body falling with a speed of 2m/s stri...

A body falling with a speed of 2m/s strikes the floor and rebounds with a speed of 1 m/s. The loss of kinetic energy is

A

`12.5%`

B

`50%`

C

`25%`

D

`75%`

Text Solution

Verified by Experts

The correct Answer is:
D
Impulse =Change in momentum
`F xx t=mv -mu-mv (therefore u=0)`
`therefore v=(Ft)/(m)`
The K.E. `=1/2mv^(2)=1/2m xx (F^(2)t^(2))/(m^(2))=(F^(2)t^(2))/(2m)`
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