A block of mass `m` at rest is acted upon by a force `F` for a time t. The kinetic energy of block after time t is

Options

A. `(F^(2)t^(2))/(2m)`
B. `(2F^(2)t^(2))/m`
C. `(F^(2)t^(2))/m`
D. `(F^(2)t^(2))/(3m)`

Answer

A

Explanation

The K.E of the body is converted into P.E.=mgh.
When its reaches the highest point, its velocity=0 and it has only P.E.
`:.` mgh=100
`:.5xx10xxh=100" "":." "h=2m`