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A body of mass 2 kg is thrown up vertica...

A body of mass `2 kg` is thrown up vertically with kinetic energy of `490 J`. If `g = 9.8m//s^(2)`, the height at which the kinetic energy of the body becomes half of the original value, is

A

50 m

B

12.25m

C

25 m

D

10 m

Text Solution

Verified by Experts

The correct Answer is:
B
Initial momentum (p)=mu
`:." "u=P/m=8/4=2m//s`
and `a=F/m=(0.02)/4=5xx10^(-2)xx10=2.5m//s`
and v=u+at=2+5`xx10^(-2)xx10=2.5m//s`
`:.` Increase in K.E=`1/2m(v^2-u^2)`
`=1/2xx4xx[(5/2)^2-2^2]`
`=2xx9/4=4.5J`
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