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A lift weighing 900 kg is to be lifted a...

A lift weighing 900 kg is to be lifted at a constant speed of 0.5 m/s. What shoud be the horse power of the motor used for running the lift?
[Use `g=10m//s^(2)` and 1 Horse power `=750` watt]

A

`2.5`

B

`4`

C

`5`

D

`6`

Text Solution

Verified by Experts

The correct Answer is:
D
Power = Force `xx` Velocity `=Fv = m xx a xx v`
But `v=u+at " " therefore v=0+at " " (because u = 0)`
`therefore P = mav=ma(at)=ma^(2)t`
`therefore P prop` as m and a are constant.
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