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A body of mass m is acceleratad uniforma...

A body of mass `m` is acceleratad uniformaly from rest to a speed `v` in a time `T` . The instanseous power delivered to the body as a function of time is given by

A

`1/2(mv^(2))/(T^(2))t^(2)`

B

`1/2(mv^(2))/(T^(2))t`

C

`(mv^(2))/(T^(2))t^(2)`

D

`(mv^(2))/(T^(2))t`

Text Solution

Verified by Experts

The correct Answer is:
D
Power `=("work done against gravitational force")/("time")`
`= (mgh)/(t)`
`m=50+10=60kg, h=15xx20=300 cm = 3m`
`therefore P=(mgh)/(t)=(60xx9.8xx3)/(10)=176.4W`
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