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A particle is projected with a velocity ...

A particle is projected with a velocity `200 m//s` at an angle of `60^(@).` At the highest point it explodes into three particle of equal masses. One goes vertically upward with a velocity `100m//s` the second particle goes vertically downwards at same speed. What is the velocity of the third particle?

A

120 m/s with `60^(@)` angle

B

200 m/s

C

300 m/s

D

200 m/s with `30^(@)` angle

Text Solution

Verified by Experts

The correct Answer is:
C
There is an elastic collision between the two billiard balls.
In this case, `m_1 =m_2 and u_2 =0`
`therefore ` After collision `v_1 =0` i.e. the first ball stops dead after collision and `v_2 =u_1` i.e. the second ball starts moving forward with a velocity `u_1=5` m/s .
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