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Two masses m(A) and m(B) moving with vel...

Two masses `m_(A)` and `m_(B)` moving with velocities `v_(A)` and `v_(B)` in opposite direction collide elastically after that the masses `m_(A)` and `m_(B)` move with velocity `v_(B)` and `v_(A)` respectively. The ratio `(m_(A)//m_(B))` is

A

`(v_(a)-v_(b))/(v_(a)+v_(b))`

B

`(v_(a)+v_(b))/(v_(a)-v_(b))`

C

`1`

D

`1/2`

Text Solution

Verified by Experts

The correct Answer is:
C
The collision is perfectly elastic and the two particles have equal masses.
`:.` After collision with the stationary particle, the first particle will stop and the other particle will move with the velocity v.
`:.` It will describe a circular path of radius r and length `2pi r ` and hit the first particle again .
`:.` The time for the next collision will be
`t = (" distance")/( "velocity")= ( 2pi r)/( v ) `
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